1. How does the force of gravitation between two objects change when the distance between them is reduced to half?

Explanation:

Think about the gravitational equation,

The rule states that the attraction between two entities is

F F=Gm1, m2r2

Where,

The two entities' respective weights are m1 and m2.

The gravity constant is called G.

r represents the separation between the two entities.

Considering that the distance is now cut in half,

r = 1/2 r

Therefore,

NCERT Solutions for Class 9 Science - Chapter 10 Image 4

F = 4F

Therefore once the space between the objects is reduced to half, then the force of gravitation will increase by fourfold the first force.


2. Gravitational force acts on all objects in proportion to their masses. Why then does a heavy object not fall faster than a light object?

Explanation:

Every item falls from the top with a steady acceleration known as gravity's acceleration. (g). since this is fixed on Earth, the number of "g" is independent of an object's mass. Therefore, in the absence of air resistance, heavier things do not descend more quickly than light-weight objects.


3. What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106m.)

Explanation:

 In accordance with Newton's rule of gravity, the power of attraction between two bodies is equal to



NCERT Solutions for Class 9 Science - Chapter 10 Image 5


4. The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is greater or smaller or the same as the force with which the moon attracts the earth? Why?

Explanation:

The same energy that pulls the moon toward the earth also pulls the earth toward the moon. These forces, though, are acting in the opposing way. According to the global rule of gravitation, there can be a pull between the moon and the sun.

NCERT Solutions for Class 9 Science - Chapter 10 Image 6

Where,


d is the distance between the moon and the planet.

The masses of the planet and the moon are m1 and m2, correspondingly.


5. If the moon attracts the earth, why does the earth not move towards the moon?

Explanation:

We all understand that the force of attraction between two things is the same, but acting in the opposite directions, in accordance with the global law of gravity and Newton's third law. In other words, the moon and earth are attracted to each other in opposite ways by the same energy. The Earth moves slower toward the Moon than the Moon does towards the Earth because the Earth has a bigger mass than the Moon.


6. What happens to the force between two objects, if

  1.  The mass of one object is doubled?

  2. The distance between the objects is doubled and tripled?

  3. The masses of both objects are doubled?

Explanation:

  1. The force between two things (m1 and m2) is proportional to their mass and reciprocally proportional to the square of their separation (R), according to the global rule of gravitation.

NCERT Solutions for Class 9 Science - Chapter 10 Image 7

If the mass of one item is increased. The power is also twice because F = 2F.


  1. Increasing and tripling the space between the items when multiplied. Hence,

F = (Gm1m2)/ (2R) 2

F = 1/4 (Gm1m2)/R2

F = F/4

Thus, energy is reduced to one-fourth of what it was initially.

If it is now quadrupled. Hence,

F = (Gm1m2)/ (3R) 2

F = 1/9 (Gm1m2)/R2

F = F/9

As a result, power decreases to 1/9 of what it was initially.


  1. If the weights of both items are increased by two, then

NCERT Solutions for Class 9 Science - Chapter 10 Image 10

Force will be four times larger than its real amount because F = 4F.


7. What is the importance of universal law of gravitation?

Explanation:

  • Many events that were thought to be unrelated are now explained by the universal rule of gravitation:

  • The moon's orbiting the planet.

  • Gravity's impact on the body's weight, which holds us on the earth.

  • The waves are caused by the moon and the sun, so they follow.

  • Planets' revolving around the Sun


8. What is the acceleration of free fall?

Explanation:

The acceleration an object experiences as a result of gravitational influence is known as acceleration owing to gravity. On Earth, the bulk of the planet imposes a downward pull on all things, known as gravity. The acceleration of things descending loosely serves as a gauge for the Earth's gravity. The acceleration of gravity is symbolized by the letter "g" and is 9.8 ms-2 at the top of the Earth. As a result, during free fall, an object's speed rises by about 9.8 meters per second.


9. What do we call the gravitational force between the earth and an object?

Explanation:

The gravitational pull of the planet on an item is measured by its weight. Weight is a gauge of the gravitational force that pulls a substance downward. The weight equation is. The body's mass and gravity force are shown here. Because weight is a force, its SI measure is also a force; the SI unit for weight is the Newton. (N).Weight may not exist. An item in space has negative weight if there is no gravitational pull on i.e. vector number is weight. It is directed at the centre of the Earth and has magnitude.


10. Amit buys few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not, why? [Hint: The value of g is greater at the poles than at the equator.]

Explanation:

a body's weight on the top of the planet;

W = mg (where m = bodily mass and g = gravitational force)

When compared to the equator, the number of g is higher at the extremes. So gold can weigh less at the equator as compared to the extremes. As a result, Amit's buddy won't believe the amount of wealth that was purchased.


11. Why will a sheet of paper fall slower than one that is crumpled into a ball?

Explanation:

The volume of the item diminishes but the mass stays the same when the paper is crumpled into a ball. Consequently, its mass rises. Both a crumpled ball and a piece of falling paper experience some resistance from the air, but the crumpled ball experiences less resistance as it travels through the air, causing it to descend more quickly.   


12. Gravitational force on the surface of the moon is only 1/6 as strong as gravitational force on the earth. What is the weight in newton’s of a 10 kg object on the moon and on the earth?

Explanation:

info provided

Gravitational acceleration = ge or g = 9.8 m/s2

Mass of the thing, m = 10 kg

Moon gravitational acceleration ꓿ gm

Earth's weight = we

Wm = Weight on the Moon

Mass times Gravity = Weight

gm = (1/6) ge (given)

Wm = m gm = m x (1/6) ge, then.

Wm = 10 x (1/6) x 9.8 = 16.34 N

We = mxge =10x9.8

We = 98N


13. A ball is thrown vertically upwards with a velocity of 49 m/s.

 Calculate

  1.  The maximum height to which it rises, 

  2. The total time it takes to return to the surface of the earth.

Explanation:

Given data:

Initial velocity u = 49 m/s

Final speed v at maximum height = 0

Acceleration due to earth gravity g = -9.8 m/s2 (thus negative as ball is thrown up).

By third equation of motion,

2gH = v2 – u2

2 × (- 9.8) × H = 0 – (49)2

– 19.6 H = – 2401

H = 122.5 m

Total time T = Time to ascend (Ta) + Time to descend (Td)

v = u + gt

0 = 49 + (-9.8) x Ta

Ta = (49/9.8) = 5 s

Also, Td = 5 s

Therefore T = Ta + Td

T = 5 + 5

T = 10 s


14. A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.

Explanation:

info provided

Initial speed

u = 0

Tower height = overall length = 19.6 meters 

g = 9.8 m/s2

Think about the third equation of motion.

v2 = u2 + 2gs

v2 = 0 + 2 × 9.8 × 19.6

v2 = 384.16

v = √ (384.16)

v = 19.6m/s


15. A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Explanation:

details provided

Initial speed, u, is 40 m/s.

g = 10 m/s2

Maximum height ultimate speed is 0.

Think about the third equation of motion.

V2 is equal to u2 - 2gs (negative as the object ascends).

0 = (40)2 – 2 x 10 x s

s = (40 x 40) / 20 

Max height is 80 meters.

Distance total = s + s = 80 + 80

160 meters total distance

Displacement overall is 0 (The first point is the same as the last point)


16. Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth = 6 × 1024 kg and of the Sun = 2 × 1030 kg. The average distance between the two is 1.5 × 1011 m.

Explanation:

 details provided

The sun's mass is 2 1030 kg.

Earth's mass, ME, is 6 1024 kilograms.

Measure of gravitation 6.67 x 10-11 N m2/kg2 = G

The typical distance is 1.5 1011 m.

Think about the Law of Gravitation.

NCERT Solutions for Class 9 Science - Chapter 10 Image 12


17.  A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.

Explanation:

details provided


  1. When the stone is hurled from the tower's summit,

Initial speed u' equals zero

Travel distance equals x

Taken time = seconds

Therefore, 

NCERT Solutions for Class 9 Science - Chapter 10 Image 13


  1. Upon throwing the stone upward,

Initial speed, u, is 25 m/travel distance = (100 – x)

Taken time = seconds

NCERT Solutions for Class 9 Science - Chapter 10 Image 14

Using the formulae (a) and (b)

5t2 = 100 -25t + 5t2

t = (100/25) = 4sec.

In 4 seconds, two stones will collide.

From (a) x = 5t2 = 5 x 4 x 4 = 80m.

Including x's value in (100-x)

= (100-80) = 20m.

This indicates that after 4 seconds, two stones will collide 20 meters above the earth.


18.  A ball thrown up vertically returns to the thrower after 6 s. Find

  1. The velocity with which it was thrown up,

  2. The maximum height it reaches, and

  3.  Its position after 4s.

Explanation:

info provided

g = 10m/s2

Total duration T = 6 seconds.

Ta=Td=3 seconds.


  1.  Maximum height with final velocity equal to zero

Using the initial velocity equation: v equals u - gta

u = v plus gta

= 0 + 10 x 3

= 30m/s

The stone was hurled up at a speed of 30 m/s.


  1.  Using the second motion solution

NCERT Solutions for Class 9 Science - Chapter 10 Image 15

The height that a stone can attain is 45 meters.


  1. It achieves its highest point in 3 seconds.

Additional 1 second's worth of journey equals s'.

NCERT Solutions for Class 9 Science - Chapter 10 Image 16

5 meters were covered in an additional 1 second. Consequently, the location of point p in 4 seconds (45 – 5) 40 meters above the earth.


19. In what direction does the buoyant force on an object immersed in a liquid act?

Explanation:

An item submerged in a liquid experiences buoyant force that works upward, which is the polar opposite of the force the object is exerting.

An item submerged in a liquid experiences buoyancy in an upward, vertical orientation. The way that buoyant force acts is the exact opposite of the direction that the item acts.


20. Why a block of plastic when released under water come up to the surface of water?

Explanation:

Plastic has a lower mass than water does. As a result, the buoyancy force acting on the plastic object will be larger than its weight. As a result, the plastic object will accelerate in an upward trajectory. Consequently, the plastic object rises to the water's top.


21. The volume of 50 g of a substance is 20 cm3. If the density of water is 1 g cm–3, will the substance float or sink?

Explanation:

The method is to determine the substance's density.

(Mass/Volume) equals density

(50/20) = 2.5g/cm3 for density

Water has a density of 1 g/cm3.

The substance's density is higher than water's density. It will therefore submerge.


22. The volume of a 500 g sealed packet is 350 cm3. Will the packet float or sink in water if the density of water is 1 g cm–3? What will be the mass of the water displaced by this packet?

Explanation:

 The packed package has a density of 500/350, or 1.42 g/cm3.

Water has a higher density than an enclosed container.

The package will consequently submerge.

In light of the Archimedes Principle,

Force applied to the enclosed container equals Volume of displaced water.

350cm3 is the volume of water expended.

Thus, shifted water mass is equal to x V.

= 1 × 350

Water displacement mass is 350g.