1. In a sporting event, a female baseball player hits the line on 6 of the 30 balls she hits. Find the probability of not hitting the limit.
1. In a sporting event, a female baseball player hits the line on 6 of the 30 balls she hits. Find the probability of not hitting the limit.
Explanation:
Based on the question,
Total balls = 30
Boundaries = 6
Number of times the female batter missed the bounds = 30 – 6 = 24
Result of the Boundary = 24/30 = 4 5
2. Randomly select 1500 families with 2 children and the following Gather the information:
Also check the probability that a randomly selected family
will have 2 girls, their sum will be 1.
2. Randomly select 1500 families with 2 children and the following Gather the information:
Also check the probability that a randomly selected family
will have 2 girls, their sum will be 1.
Explanation:
Total family = 1500
Family with 2 girls = 475
Probability = Family with 2 girls / Total family
= 475/1500 = 19/60
3. 1500 families have 2 children Random. select, enter the following information:
Any family outcome, randomly selected,
1 girl
Also check the number of these probabilities is 1.
3. 1500 families have 2 children Random. select, enter the following information:
1 girl
Also check the number of these probabilities is 1.
Explanation:
Families with 1 daughter = 814
Probability = Families with 1 daughter / all families
= 814/1500 = 407/750
4. Randomly select 1500 families with 2 children and write the following data:
Calculate the probability that a randomly selected family will have
0 girl
Also check that these results add up to 1.
4. Randomly select 1500 families with 2 children and write the following data:
Calculate the probability that a randomly selected family will have
0 girl
Also check that these results add up to 1.
Explanation:
Families with 0 girls = 211
Probability = Families with girls 0 girls / total families
= 211/ 1500
Outcomes = (19/60)+(407/750)+(211/1500)
= (475 + 814 + 211) / 1500
= 1500 / 1500 = 1
Yes , the result of the result This ratio is 1
5. Toss three coins 200 times at the same time, the difference is:
If three coins are tossed in the same direction . Time Toss a coin, calculate the probability of getting
2 heads
5. Toss three coins 200 times at the same time, the difference is:
If three coins are tossed in the same direction . Time Toss a coin, calculate the probability of getting
Explanation:
Number of 2 heads = 72
Total number of coins waiting = 200
∴, probability of getting 2 heads = 72/200 = 9/25
6. An organization Randomly selected 2400 families. A study to determine the relationship between income level and car in a family. The collected data are shown in the table below:
Family is selected.
The probability of finding a chosen family is
(a) earning Rs 10000 to 13000 per month and owning 2 cars.
(b) Earn Rs 16000 or more per month and own 1 car. Income less than Rs
(c). 7000 per month and no cars.
(d) Earn Rs 13000-16000 per month and own more than 2 cars.
(e) Not having more than 1 vehicle.
6. An organization Randomly selected 2400 families. A study to determine the relationship between income level and car in a family. The collected data are shown in the table below:
Family is selected.
The probability of finding a chosen family is
(a) earning Rs 10000 to 13000 per month and owning 2 cars.
(b) Earn Rs 16000 or more per month and own 1 car. Income less than Rs
(c). 7000 per month and no cars.
(d) Earn Rs 13000-16000 per month and own more than 2 cars.
(e) Not having more than 1 vehicle.
Explanation:
Total number of families = 2400
(a) Families with a monthly income of Rs. Capacity of one car 2 cars = 29/2400
(b) Households with monthly income of Rs. One car probability = 579/2400
(c) Houses with Salary less than Rs. 7000 and without a car = ∴10
, Can choose a family whose monthly income is below Rs. 7000 without cars = 10/2400 = 1/2 240
(d) Households with a monthly income of 13000-16000 rupees and more than 2 cars = 25
∴, selected households with a monthly income of 13000-16000 rupees and more than 1 car with = 25/2400 = 1/96
(e) Households without more than 1 car = 10+160+ 0+305+1+535+2+469+1+579
= 2062
∴, Probability of Selection of More than One House
He Doesn't Have Many Cars = 2062/2400 = 1031/1200
7. A survey was conducted with 200 students to understand the students' views on statistics. The information is recorded in the table below.
Find the probability that the selected students (a) likes and (ba dislikes the issue.
7. A survey was conducted with 200 students to understand the students' views on statistics. The information is recorded in the table below.
Explanation:
Total students = 135 + 65 = 200
(ai Student who likes statistics = 135
Student who likes statistics = 135/200 = 27/40
(b) Student who doesn't like statistics = 65
∴, probability that a student doesn't like statistics = 65/200 = 13/40
8. Activity: Note how many two-wheeled, three-wheeled and four-wheeled vehicles pass through the school gates. Find the probability that one of the cars you are looking at has two wheels.
8. Activity: Note how many two-wheeled, three-wheeled and four-wheeled vehicles pass through the school gates. Find the probability that one of the cars you are looking at has two wheels.
Explanation:
This question is a student activity.
So you do the work yourself and remember why.
9. Activity: Ask each student in the class to write a 3-digit number. Choose a random student from the room. What is the probability that the number he
wrote is divisible by 3? Note that the number is divisible by 3 if the sum of the digits is divisible by 3.
9. Activity: Ask each student in the class to write a 3-digit number. Choose a random student from the room. What is the probability that the number he
wrote is divisible by 3? Note that the number is divisible by 3 if the sum of the digits is divisible by 3.Explanation:
his question is an exercise for students to complete.
So do the work yourself and remember why.
Also Read: Class 9 Probability Extra Questions
