1. The following are the car parking charges near a railway station up to,
4 hours – Rs.60
8 hours – Rs.100
12 hours – Rs.140
24 hours – Rs.180
Check if the parking charges are in direct proportion to the parking time.
Explanation:
Charge per hour:
i). Rs 60 for 4 hours- 60/4
= Rs. 15
ii) Rs 100 for 8 hours- 100/8
= Rs. 12.50
iii) Rs 140 for 12 hours- 140/12
= Rs. 11.67
iv) Rs 180 for 24 hours- 180/24
= Rs 7.50
Since, the per hour charge in the above cases are not same,i.e., i≠ii≠iii≠iv
Therefore, the parking charges are not in direct proportion with the parking time.
2. A mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of the base. In the following table, find the parts of the base that need to be added.
Explanation:
Let the ratio of parts of red pigment to the part of base be a:b and we denote a:b as k
Case 1-
Here, 1 part of red pigment is mixed with 8 parts of base
Thus, k= 1:8 or 1 / 8; a1=1, b1= 8
Case 2,
Here, k= 4:?; a2=4, b2= ?
K= a2 / b2
1 / 8 =4 / b2
b2= 32
Case 3,
Here k= 7:?; a3= 7, b3= ?
K= a3 / b3
1/ 8 = 7/ b3
b3= 56
Case4,
Here k= 12:?; a4= 12, b4= ?
K= a4 / b4
1/ 8 = 12/ b4
b4= 96
Case 5,
Here k= 20:?; a4= 20, b4= ?
K= a5/ b5
1/8 = 20/b5
b5=160
Combining results for all the cases, we get
3. In Question 2 above, if 1 part of a red pigment requires 75 mL of the base, how much red pigment should we mix with 1800 mL of the base?
Explanation:
Let part of red pigment mixed with 1800ml of base be x
75ml of base= 1 part of pigment
1800ml of base= x part of pigment
Since, it is in direct proportion
1 / 75 = x / 1800
75x= 1800
x=1800/75
x=24
Hence, 24 parts of red pigment should be mixed with base of 1800ml.
4. A machine in a soft drink factory fills 840 bottles in six hours. How many bottles will it fill in five hours?
Explanation:
In 6hrs, the machine fills 840 bottles
In 1hr, the machine will fill 840/6 bottles or 140 bottles
Per hour yield of machine is 140 bottles
In 5 hours, the machine will fill 140x5 bottles or 700 bottles.
5. A photograph of a bacteria enlarged 50,000 times attains a length of 5 cm, as shown in the diagram. What is the actual length of the bacteria? If the photograph is enlarged 20,000 times only, what would be its enlarged length?
Explanation:
Let enlarged length of bacteria be x
Actual length of bacteria= 5/50,000 cm
= 1/10,000 cm
= 10-4 cm
Bacteria enlarged 50,000 times attains length of 5cm
Bacteria enlarged 20,000 times, attains length of x cm
Here, the length and enlarged length of bacteria is in direct proportion
5/50,000 = x/20,000
50,000x = 1,00,000
X= 2
Hence, the enlarged length of bacteria is 2cm.
6. In a model of a ship, the mast is 9 cm high, while the mast of the actual ship is 12 m high. If the length of the ship is 28 m, how long is the model ship?
Explanation:
Let the length of model ship be x cm
Length of actual ship= 28m; mast of actual ship= 12m
Length of model ship= x cm; mast of model ship= 9cm
Since, the length of the mast and the actual length of the ship are in direct proportion.
12/9 =28/x
12x= 252
x= 21
Hence, the length of model ship is 21cm.
7. Suppose 2 kg of sugar contains 9×106 crystals. How many sugar crystals are there in
(i) 5 kg of sugar? (ii) 1.2 kg of sugar?
Explanation:
i) Let crystal content in 5kg sugar be x
And 2kg sugar contains 9×106 crystal
Here, the weight of sugar and the number of crystals are in direct proportion.
2x= 9 x 5 x 106
x= 9 x 5 x 106
2
x= 22.5 x 106
x= 2.25 x 107
Hence, the number of sugar crystals is 2.25 x 107
ii)
Let sugar crystals in 1.2kg sugar be x.
And 2kg sugar contains 9×106 crystal
Here, the weight of sugar and the number of crystals are in direct proportion.
2x= 1.2 x 9 x 106
x= 1.2 x 9 x 106
2
x= 5.4 x 106
Hence, the number of sugar crystals is 5.4 x 106
8. Rashmi has a road map with a scale of 1 cm representing 18 km. She drives on the road for 72 km. What would be her distance covered on the map?
Explanation:
Let the distance covered in the map be x
Here, the actual distance and distance covered in the map are in direct proportion.
18/1 = 72/x
18x= 72
x= 4
Hence, the distance covered on the map is 4 cm.
9. A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time (i) the length of the shadow cast by another pole 10 m 50 cm high (ii) the height of a pole which casts a shadow 5 m long.
Explanation:
(i) Height of pole= 5m 60cm or 560cm (Since 1m=100cm)
Length of shadow it casts= 3m 20cm or 320cm
Height of another pole= 10m 50cm
Let the length of the shadow of another pole be x.
Here, the height of the pole and the length of the shadow are in direct proportion.
560320 = 1050x
=> 560x= 1050 x 320
=> x= 1050 x 320
560
x= 600 cm = 6m
Hence, the length of the shadow of another pole is 6 m.
(ii) Let the height of the pole be x.
Length of its shadow= 5m or 500cm
560320 = x500
=> x= 500 x 560
320
= 875 cm
= 8 m 75 cm
Hence, the height of the pole is 8 m 75 cm.
10. A loaded truck travels 14 km in 25 minutes. If the speed remains the same, how far can it travel in 5 hours?
Explanation:
Let the distance covered in 5 hours be x km.
1 hour = 60 minutes
Therefore, 5 hours = 5×60 = 300 minutes
Here, the distance covered and time are in direct proportion.
1425 = x300
25x = 300 x 24
x = 168
Therefore, the truck can travel 168 km in 5 hours.
Exercise 13.2
11.Which of the following are in inverse proportion?
(i) The number of workers on a job and the time to complete the job.
(ii) The time taken for a journey and the distance travelled at a uniform speed.
(iii) Area of cultivated land and the crop harvested.
(iv) The time taken for a fixed journey and the speed of the vehicle.
(v) The population of a country and the area of land per person.
Explanation:
i) The number of workers on a job and time to complete the job are in inverse proportion because if more are the number of workers less time will be taken to complete the job and vice versa.
ii) Time taken for a journey and distance travelled is directly proportional because with more time more distance can be covered.
iii) It is direct proportion because more area of cultivated land will yield more harvest.
iv) Speed and time are in inverse proportion because with more speed less time will be taken.
v) It is inverse proportion because with an increase in population the area of land per person decreases.
12. In a Television game show, the prize money of Rs.1,00,000 is to be divided equally amongst the winners. Complete the following table and find whether the prize money given to an individual winner is directly or inversely proportional to the number of winners:
Explanation:
Here, the number of winners and prize money are in inverse proportion because prize money is decreasing with increase in number of winners.
When there are 4 winners, each winner will get =100000/4 = Rs. 25,000
When there are 5 winners, each winner will get =100000/5 = Rs. 20,000
When there are 8 winners, each winner will get =100000/8 = Rs. 12,500
When there are 10 winners, each winner will get = 100000/10 = Rs. 10,000
When there are 20 winner, each winner will get = 100000/20 = Rs. 5,000
13. Rehman is making a wheel using spokes. He wants to fix equal spokes in such a way that the angles between any pair of consecutive spokes are equal. Help him by completing the following table:
(i) Are the number of spokes and the angles formed between the pairs of consecutive spokes in inverse proportion?
(ii) Calculate the angle between a pair of consecutive spokes on a wheel with 15 spokes.
(iii) How many spokes would be needed, if the angle between a pair of consecutive spokes is 40 degree?
Explanation:
a) When there are 4 spokes, then the angle between a pair of consecutive spokes = 360/4 = 90 degree
b) When there are 8 spokes, then the angle between a pair of consecutive spokes = 360/8= 45 degree.
C) When there are12 spokes, then the angle between a pair of consecutive spokes = 360/12 = 30 degree.
(i) Yes, the number of spokes and the angles formed between a pair of consecutive spokes is in inverse proportion as it is clear above that as the number of spokes is increasing, the angle between a pair of consecutive spokes is decreasing.
(ii) When the number of spokes is 15, then the angle between a pair of consecutive spokes = 360/15= 24 degree.
(iii) If the angle between a pair of consecutive spokes is 40 degree, then number of spokes required will be 360/40= 9 spokes
14. If a box of sweets is divided among 24 children, they will get 5 sweets each. How many would each get, if the number of children is reduced by 4?
Explanation:
When each child gets 5 sweets, 24 children will get 24 x 5 sweets, i.e., 120 sweets
Therefore, total number of sweets= 120
When the number of students is reduced by 4, then the children left is ( 24-4) or 20
Noe, each child will get 120/20 sweets, i.e., 6 sweets.
15. A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?
Explanation:
20 animals can be fed for 6 days.
When total number of animals is increased by 10, let us assume that they can be fed for x days.
Here, the number of animals and the number of days are in inverse proportion.
2030 = x6
30x = 120
x = 4
Hence, the food will last for 4 days.
16. A contractor estimates that 3 persons could rewire Jasminder’s house in 4 days. If he uses 4 persons instead of three, how long should they take to complete the job?
Explanation:
Let the time taken to complete the job by 4 person be x.
Here, the number of persons and the number of days are in inverse proportion.
3/4= x/4
3×4 = 4x
x = 3
Hence, it will take 3 days to complete the job by 4 person.
17. A batch of bottles was packed in 25 boxes, with 12 bottles in each box. If the same batch is packed using 20 bottles in each box, how many boxes would be filled?
Explanation:
Let the number of boxes filled with 20 bottles in each box be x.
Here, the number of bottles and the number of boxes are in inverse proportion.
12/20 = x/25
20x=12×25
x = 12×25/20 = 15
Hence, 15 boxes would be filled.
18. A factory requires 42 machines to produce a given number of articles in 63 days. How many machines would be required to produce the same number of articles in 54 days?
Explanation:
Let the number of machines required be x.
Here, the number of machines and the number of days are in inverse proportion.
63/54 = x/42
63×42 = 54x
x = 63×42/54
x= 49
Hence, 49 machines would be required.
19. A car takes 2 hours to reach a destination by travelling at the speed of 60 km/hr. How long will it take when the car travels at the speed of 80 km/hr?
Explanation:
Let the number of hours be x when speed is 80km/hr
Here, the speed of the car and time are in inverse proportion.
60/80 = x/2
60×2 = 80x
x = 60×2/80
x= 3/2
x= 1.5
Hence the car will take 1.5 hours to reach its destination.
20. Two persons could fit new windows in a house in 3 days.
(i) One of the persons fell ill before the work started. How long would the job take now?
(ii) How many persons would be needed to fit the windows in one day?
Explanation:
(i) Let the number of days be x.
Here, the number of persons and the number of days are in inverse proportion.
2/1 = x/3
x = 6
Hence, when one person fell ill the same job will take 6 days now.
(ii) Let the number of persons be x.
Here, the number of persons and the number of days are in inverse proportion.
2/x = 1/3
x = 6
Hence, to fit the window in one day 6 person would be needed.
21. A school has 8 periods a day, each of 45 minutes duration. How long would each period be, if the school has 9 periods a day, assuming the number of school hours to be the same?
Explanation:
Let the duration of each period be x when school has 9 periods a day.
Here, the number of periods and the duration of periods are in inverse proportion.
8/9 = x/45
9x= 8 x 45
x = 40
Hence, the duration of each period would be 40 minutes.