1. Define the principal focus of a concave mirror.

Explanation:

The principal focus of a concave mirror refers to the point on its principal axis where parallel rays of light incident on the mirror tend to converge after being reflected. It is a focal point that can be found halfway between the center of curvature and the vertex of the mirror. The symbol "F" represents the principal focus and its distance from the vertex of the mirror are represented by "f". The principal focus is a concept of importance in optics because it is used to determine the magnification and image formation in optical systems that make use of concave mirrors.

2. The radius of curvature of a spherical mirror is 20 cm. What is its focal length?


Explanation:

For a spherical mirror, the radius of curvature (R) and focal length (f) are related by the equation-

1/f = 2/R

Substituting R=20 cm in the above formula, we get-

1/f = 2/20 cm

Simplifying the right-hand side, we get:

1/f = 0.1 cm^-1

Taking the reciprocal of both sides, we get:

f = 10 cm

Hence, 10 cm is the focal length of the spherical mirror.

3. Name a mirror that can give an erect and enlarged image of an object.

Explanation:

A concave mirror can give an erect and enlarged image of an object placed at a certain distance from the mirror. The distance of the object from the mirror and the focal length of the mirror determine the size and orientation of the image formed by the mirror. A concave mirror is also called a converging mirror because it converges light rays that fall on it.

4. Why do we prefer a convex mirror as a rear-view mirror in vehicles?

Explanation:

We prefer convex mirrors as rear-view mirrors in vehicles because they provide a wider field of view than flat mirrors.

A convex mirror is curved outward, which means that it reflects light outwards and creates a smaller, more distorted image of the objects behind us. However, this distortion allows the mirror to reflect a wider field of view than a flat mirror, which only reflects a narrow area directly behind the vehicle.

This wider field of view allows the driver to see more of the surrounding area, which can be particularly useful when changing lanes or maneuvering in tight spaces. Additionally, the distorted image created by the convex mirror can make it easier to judge distances between objects, which can be especially helpful when parking or backing up.

In conclusion, the convex mirror provides a safer and more effective rear-view mirror for drivers, which is why it is preferred in vehicles.

5. Find the focal length of a convex mirror whose radius of curvature is 32 cm.

Explanation:

For a convex mirror, the focal length (f) is half the radius of curvature (R). Therefore, in this case, the focal length is-

f = R/2 = 32 cm / 2 = 16 cm

So the focal length of the convex mirror is 16 cm.

6. A concave mirror produces three times magnified (enlarged) real image of an object placed 10 cm in front of it. Where is the image located?

Explanation:

We can use the mirror formula to solve this problem, which is-

1/f = 1/v + 1/u

where f is the focal length of the mirror, v is the distance of the image from the mirror, and u is the distance of the object from the mirror.

Since the mirror is concave and produces a real image, the focal length is negative. We are also given that the magnification of the image is 3, which means-

magnification = v/u = 3

Using these two equations, we can solve for v and u. Substituting v = 3u into the mirror formula, we get-

1/f = 1/3u + 1/u

Simplifying this equation, we get-

1/f = 4/3u

Multiplying both sides by u, we get-

u/f = 4/3

Substituting u = 10 cm, we get-

10/f = 4/3

Solving for f, we get-

f = -7.5 cm

So the focal length of the mirror is -7.5 cm. Now the magnification equation can be used to find the distance of the image from the mirror-

v/u = 3

v/10 = 3

v = 30 cm

Hence, the real image which is produced by the concave mirror is situated at a distance of 30 cm behind the mirror.

7. A ray of light traveling in the air enters obliquely into water. Does the light ray bend towards the normal or away from the normal? Why?

Explanation:


The light beam sways in the direction of normal.

A light beam is bent towards the normal when it moves from an optically rarer to an optically denser medium. Air is optically denser than water, hence a light ray traveling from the air would hit water and bends towards the average when it goes into the water.


8. Light enters from air to glass having a refractive index of 1.50. What is the speed of light in the glass? The speed of light in a vacuum is 3 × 108 m s−1.

Explanation:

Speed of light in vacuum divided by speed of light in medium gives the refractive index of a medium (nm).

The vacuum-bound speed of light (c) is 3 × 108 m/s.

Glass has a refractive index of 1.50 (ng).

Speed of light in glass (v) = Vacuum speed of light/Glass refractive index

= c/ng

=3 × 108/1.50 = 2x 108 ms-1.

9. Find out from the Table, the medium has the highest optical density. Also, find the medium with the lowest optical density.

Material

medium

Refractive index

Material medium

Refractive

index

Air

1.0003

Canada Balsam

1.53

Ice

1.31

Water

1.33

Rock salt

1.54

Alcohol

1.36

Kerosene

1.44

Carbon disulfide

1.63

Fused

quartz

1.46

Dense

flint glass

1.65

Turpentine oil

1.47

Ruby

1.71

Benzene

1.50

Sapphire

1.77

Crown

glass

1.52

Diamond

2.42

Explanation:

Diamond has the highest optical density.

The most transparent substance is air.

A medium's refractive index and optical density are intimately correlated. The largest optical density will be found in a medium with the highest refractive index, and vice versa.

Table 10.3 shows that the refractive indices of air and diamond are the highest and lowest, respectively. As a result, the air has the lowest optical density while the diamond has the highest.

10. You are given kerosene, turpentine, and water. In which of these does the light travel fastest? Use the information given in Table. 

Material

medium

Refractive index

Material medium

Refractive

index

Air

1.0003

Canada Balsam

1.53

Ice

1.31

Water

1.33

Rock salt

1.54

Alcohol

1.36

Kerosene

1.44

Carbon disulphide

1.63

Fused

quartz

1.46

Dense

flint glass

1.65

Turpentine oil

1.47

Ruby

1.71

Benzene

1.50

Sapphire

1.77

Crown

glass

1.52

Diamond

2.42

Explanation:

The relationship for a refractive index determines the speed of light in a given medium (nm). The relationship is provided as

From the relationship, it can be deduced that light moves the slowest through materials with high refractive indices and the fastest via those with low indices.

Table 10.3 shows that kerosene, turpentine, and water have corresponding refractive indices of 1.44, 1.47, and 1.33. Light moves through water the fastest, for this reason.

11. The refractive index of diamonds is 2.42. What is the meaning of this statement?

Explanation:

The relationship between a medium's refractive index (nm) and its light speed (v) is as follows:



c is the speed of light in a vacuum or in air.

Diamond has a refractive index of 2.42. This implies that compared to the speed of light in air, the speed of light in diamonds will be reduced by a ratio of 2.42.

12. Define 1 dioptre of power of a lens.

Explanation:

P=1/F(in meters)

The reciprocal of a lens's focal length is referred to as the lens' power. The SI unit for lens power is the dioptre if P is the power of a lens with a focal length of fin metres. D stands for it.

The power of a lens with a 1-meter focal length is referred to as 1 dioptre.

1 D = 1 m−1

13. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also, find the power of the lens.

Explanation:

A convex lens's opposite side's center of curvature, 2F2, creates the image of an object placed in the center of curvature, 2F1, of the lens. As seen in the given illustration, the picture that forms is inverted and the same size as the object.


Since the image is true and the same size, it should be in position 2F.

It is assumed that the needle's image is produced 50 cm away from the convex lens. As a result, the needle is positioned 50 cm in front of the lens.

Distance to object (u) = -50 cm

50 cm is the image distance (v).

f = focal length

The formula for the lens states that


14. Find the power of a concave lens of focal length 2 m.

Explanation:

The concave lens's focal length is 2 metres.

Power of lens (P) = 1/f = 1/ (-2) = -0.5D

Due to the concave lens's divergent nature in this instance, a negative sign develops.

Hence, the supplied concave lens has a power of -0.5 D.

15. Which one of the following materials cannot be used to make a lens? (a) Water (b) Glass (c) Plastic (d) Clay

Explanation:

(d) A lens enables the passage of light through it. Clay lacks this quality, hence it can't be utilized to manufacture lenses.

A lens is a transparent piece of glass that, when light rays pass through it by refraction, concentrates or disperses the light.

Clay cannot be used to create lenses because it is an opaque substance that does not allow light to pass through.

16. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object? (a) Between the principal focus and the centre of curvature (b) At the centre of curvature (c) Beyond the centre of curvature (d) Between the pole of the mirror and its principal focus

Explanation:

The right response is (d). Between the pole of the mirror and its principal focus

Development of an image (virtual, erect, and larger than the object)

It is noted that a concave mirror produces the following image:

Concave mirrors can create virtual images, but only if something is positioned in front of the focal point.

Image formation: A concave mirror produces an erect image when an object is positioned between the concave mirror's pole and its focus.

Concave mirrors provide a magnified image that is only larger than the object when it is positioned between the mirror's pole and its main focus.

Conclusion→

Consequently, only when the object is positioned between the mirror's pole and its primary focus would the image created by a concave mirror be virtual, erect, and larger than the object.

Thus, choice (d) is the right one.

17. Where should an object be placed in front of a convex lens to get a real image of the size of the object? (a) At the principal focus of the lens (b) At twice the focal length (c) At infinity (d) Between the optical center of the lens and its principal focus.

Explanation:

(b) An object's image is created at the center of curvature on the opposite side of a convex lens when it is put at the center of curvature in front of the lens. The resulting image is accurate, upside-down, and the same size as the original object.

18. A spherical mirror and a thin spherical lens have each a focal length of −15 cm. The mirror and the lens are likely to be (a) both concave (b) both convex (c) the mirror is concave and the lens is convex (d) the mirror is convex, but the lens is concave

Explanation:

(a) It is customary to interpret the focal length of a concave mirror and a concave lens as negative. As a result, the narrow spherical lens and the spherical mirror are both concave in shape.

19. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be (a) plane (b) concave (c) convex (d) either plane or convex

Explanation:

(d) A convex mirror always projects a smaller, more erect, virtual version of the item in front of it. Similar to this, a plane mirror will always reflect an upright, virtual picture of the same size as the thing in front of it. As a result, the offered mirror could be convex or planar.

20. Which of the following lenses would you prefer to use while reading small letters found in a dictionary? (a) A convex lens of focal length 50 cm (b) A concave lens of focal length 50 cm (c) A convex lens of focal length 5 cm (d) A concave lens of focal length 5 cm

Explanation:

(c) When a convex lens is positioned between the radius of curvature and the focal length, it produces a magnified image of the object. Moreover, convex lenses with shorter focal lengths magnify more. Hence, a convex lens with a 5 cm focal length should be used for reading small print.

21. We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object? Draw a ray diagram to show the image formation in this case.

Explanation:

Object distance range: 0 to 15 cm

When an object is put between a concave mirror's pole (P) and the main focus, the picture is upright (F).

So, the object must be positioned anywhere between the pole and the focus of a concave mirror with a 15 cm focal length in order to produce an erect image of it. As seen in the above graphic, the image that is created will be virtual, erect, and magnified in nature.

22. Name the type of mirror used in the following situations. (a) Headlights of a car (b) Side/rear-view mirror of a vehicle (c) Solar furnace Support your answer with reason.

Explanation: 

(a) Concave (b) Convex (c) Concave

(a) A car's headlights have concave mirrors. This is due to the fact that concave mirrors when the light source is positioned at their primary focus, can produce a strong parallel beam of light.

(b) A vehicle's side/rear view mirrors use convex mirrors. Convex mirrors to reflect the items in front of them in a virtual, elevated, and decreased form. They have a broad field of view as a result. It allows the motorist to view the majority of the traffic in front of them.

(c) Mirrors that are concave are convergent mirrors. They are utilised to build solar furnaces because of this.

The light that strikes concave mirrors converges at a single location known as the principle focus.

They can therefore be utilized to generate a lot of heat at that location.

23. One-half of a convex lens is covered with black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations.

Explanation:

Even if an object's half is covered with black paper, the convex lens will still create a complete image of the thing. It can be understood by using the next two examples.

Case I: Coverage of the upper half of the lens

In this scenario, the lower portion of the lens will bend a light ray originating from the item.

As seen in the following diagram, these rays collide on the other side of the lens to create the image of the target object.

Case II: When the lens's lower half is obscured

In this instance, the upper portion of the lens bends a light ray coming from the item. As seen in the following diagram, these rays collide on the other side of the lens to create the image of the target object.

24. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size, and nature of the image formed.

Explanation:

The object's height is h0 = 5 cm.

Object's separation from converging lens, u = -25 cm

A converging lens's focal length is 10 cm.

By applying the lens formula,


As a result, the image is inverted, generated 16.7 cm behind the lens, and is 3.3 cm in size. Below is a diagram of the rays.

25. A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.

Explanation:

Concave lens's (OF1) f = - 15 cm focal length

Image separation, v=–10 cm

The formula for the lens states that

The item is 30 cm in front of the lens according to the negative value of u. The ray diagram that follows demonstrates this.

26. An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.

Explanation:

The Convex mirror's focal length (f) is +15 cm

Distance to object (u) = -10 cm

The mirror formula says that

On the opposite side of the mirror, the picture is situated 6 cm away from the mirror.

A plane mirror produces a +1 magnification. It demonstrates that the plane mirror's created image is the same size as the object. The affirmative signal demonstrates that the produced image is virtual and upright.

27. The magnification produced by a plane mirror is +1. What does this mean?

Explanation:

A plane mirror has a magnification of +1, meaning that the size of the image it creates is exactly equal to the size of the item that is generated behind the mirror.

The affirmative signal demonstrates that the produced image is virtual and upright.

28. An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror with a radius of curvature of 30 cm. Find the position of the image, its nature and size.

Explanation:

Distance to object (u) = -20 cm

Height of object (h) = 5 cm

30 cm is the radius of curvature (R).

Focal length = 2 Radius of Curvature

R = 2f

f = 15 cm

The mirror formula says that

The picture formed is upright if the image height value is positive.

As a result, the image created is smaller, more synthetic, and more erect.

29. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of a focal length of 18 cm. At what distance from the mirror should a screen be placed, so that a sharply focused image can be obtained? Find the size and the nature of the image.

Explanation:

Distance to object (u) = – 27 cm

Height of object (h) = 7 cm

Focusing distance (f) = -18 cm

The mirror formula says that

The inverted nature of the image is indicated by a negative image height value.

30. Find the focal length of a lens of power −2.0 D. What type of lens is this?

Explanation:

A lens with a power of -2.0D has a focal length of -0.5m. The lens is concave.

The reciprocal of the lens's meter-long focal length is used to calculate its power (m).

Power of lens = 1/ focal length in meter.

Lens power (P) equals 1/f

P = -2D

f = -1/2 = -0.5 m

A concave lens has a negative focal length. As a result, it is a concave lens.

31. A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?

Explanation:

Lens power (P) equals 1/f

P = 1.5D

f = 1/1.5 = 10/15 = 0.66 m

The focal length of a convex lens is positive. It is a convex lens or a converging lens as a result.

Chapter-10, Light - reflection and refraction